Submission #2407426

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Source Code Expand

#include <cstdio>
#include <iostream>
using namespace std;

long long x[100010];

int main(){
  int n; long long k;
  cin >> n >> k;
  for (int i = 0; i < n; i++) {
    int a; long long b;
    cin >> a >> b;
    x[a] += b;
  }
  for (int i = 0; i < 100010; i++) {
    k -= x[i];
    if (k <= 0) {
      printf("%d\n", i);
      return 0;
    }
  }
  return 0;
}

Submission Info

Judge Result